(4b+7)+(b^2-3b+8)=

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Solution for (4b+7)+(b^2-3b+8)= equation:


Simplifying
(4b + 7) + (b2 + -3b + 8) = 0

Reorder the terms:
(7 + 4b) + (b2 + -3b + 8) = 0

Remove parenthesis around (7 + 4b)
7 + 4b + (b2 + -3b + 8) = 0

Reorder the terms:
7 + 4b + (8 + -3b + b2) = 0

Remove parenthesis around (8 + -3b + b2)
7 + 4b + 8 + -3b + b2 = 0

Reorder the terms:
7 + 8 + 4b + -3b + b2 = 0

Combine like terms: 7 + 8 = 15
15 + 4b + -3b + b2 = 0

Combine like terms: 4b + -3b = 1b
15 + 1b + b2 = 0

Solving
15 + 1b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-15' to each side of the equation.
15 + 1b + -15 + b2 = 0 + -15

Reorder the terms:
15 + -15 + 1b + b2 = 0 + -15

Combine like terms: 15 + -15 = 0
0 + 1b + b2 = 0 + -15
1b + b2 = 0 + -15

Combine like terms: 0 + -15 = -15
1b + b2 = -15

The b term is 1b.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
b + 0.25 + b2 = -15 + 0.25

Reorder the terms:
0.25 + b + b2 = -15 + 0.25

Combine like terms: -15 + 0.25 = -14.75
0.25 + b + b2 = -14.75

Factor a perfect square on the left side:
(b + 0.5)(b + 0.5) = -14.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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